Webcom.alibaba.fastjson.JSONArray. Best Java code snippets using com.alibaba.fastjson. JSONArray.remove (Showing top 19 results out of 315) WebOct 16, 2016 · Ideally, this would allow you to deserialize like this: Dictionary dictionary = fastJSON.JSON.ToObject> (jsonText); Unfortunately, it seems that fastJSON cannot handle this (I tried it and got an exception). However, if you switch to a more robust library like Json.Net, it works with no problem:
Jackson JsonMappingException: Can not deserialize instance
WebDec 10, 2024 · What you are doing wrong is that Dto instance variables should be according to name in Json or you should use @JsonProperty ("nameInTheJson"). If you want to make it compatible to your JSON you can just use Array of CurrencyDTO You will be able to deserialise, you can use the object as, WebMar 9, 2016 · Clearly, the JSON parser is unable to parse your JSON. Try validating the JSON at http://jsonlint.com/ to see what the problem is. As others have mentioned, you have an extraneous set of quotes just inside your initial square brackets. You must remove these. home sweet home decorative prints
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WebSounds like you have start array token [in your JSON but your java class expects a string. Map it to a String[] or List maybe ... Can not deserialize instance of java.lang.String out of START_ARRAY token at [Source: line: 1, column: 1095] (through reference chain: JsonGen["platforms"]) WebDec 9, 2024 · 0. Firstly, Your JSON is an array of CurrencyDTO, not just a CurrencyDTO as mentioned in the comment and now if it's affecting other parts of your code and you … home sweet home earl scruggs